(A) 60
(B) 70
(C) 75
(D) 80
(E) 100
Total work (man-Hours) = 100*10 = 1000 [mH]
work done in 20 days by 10 people = 250 [mH]
20 days - 250 [mH] -10 people
x days - 750 [mH] - 8 people
x = 20*(750/250)*(10/8) = 75 days
C
Rate Time Distance with [ Ratio ] GMAT, GRE, SAT problem
A contractor undertakes to do a job within 100 days and hires 10 people to do it. After 20 days, he realizes that one fourth of the work is done so he fires 2 people. In how many more days will the work get over?
(A) 60
(B) 70
(C) 75
(D) 80
(E) 100
Total work (man-Hours) = 100*10 = 1000 [mH]
work done in 20 days by 10 people = 250 [mH]
20 days - 250 [mH] -10 people
x days - 750 [mH] - 8 people
x = 20*(750/250)*(10/8) = 75 days
C
(A) 60
(B) 70
(C) 75
(D) 80
(E) 100
Total work (man-Hours) = 100*10 = 1000 [mH]
work done in 20 days by 10 people = 250 [mH]
20 days - 250 [mH] -10 people
x days - 750 [mH] - 8 people
x = 20*(750/250)*(10/8) = 75 days
C
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