A. 26
B. 39
C. 42
D. 65
E. 156
2^5, 3^3, and 13^2 are all factors of the product of 936 and w
936= 2^3 *3^2 *13^1
So, we're left with 2^2*3*13=156
you need is 2 more 2's, 1 more 3 and 1 more 13
E
E
GMAT, GRE Powers And Integers Quantitative Question
If 2^5, 3^3, and 13^2 are all factors of the product of 936 and w where w is a positive integer, what is the smallest possible value of w?
A. 26
B. 39
C. 42
D. 65
E. 156
2^5, 3^3, and 13^2 are all factors of the product of 936 and w
936= 2^3 *3^2 *13^1
So, we're left with 2^2*3*13=156
A. 26
B. 39
C. 42
D. 65
E. 156
2^5, 3^3, and 13^2 are all factors of the product of 936 and w
936= 2^3 *3^2 *13^1
So, we're left with 2^2*3*13=156
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